You are asking the wrong question. What you need to focus on when asking this question is amplifier efficiency rather than just the impedance of the load. If both amplifiers were the same efficiency into those respective impedance loads, there would be zero difference in current draw. What ibanender is likely eluding to is that most class D amplifiers will be more efficient at 4ohm than 1ohm, so the 4ohm impedance would likely result in less current draw. But the reason is because of the difference in efficiency, not impedance. It just so happens that efficiency is generally correlated with the impedance of the load the amplifier is driving. The same difference in current draw could occur between two different amplifiers of the same power driving the same load simply because of a difference in efficiency between the two amplifiers. So, moral of the story.....current draw is directly related to efficiency, not load. Efficiency is generally correlated with the load (lower the load, lower the efficiency). But efficiency of different designs and amplifiers will be different, so driving a higher impedance load does not guaranty a higher efficiency when comparing two different amplifiers. excellent !!!
