You can manually calculate port length with: Note that enclosure volume is net, and in cubic inches, so multiply your volume in cubic feet by 1728 to get cubic inches for Vb. Port area has to be converted to radius of circle in inches. Since area of circle is pi*r^2, you can translate your port area in squared inches to radius of circle by dividing by pi, and square rooting. IE: 2.92ft^3 volume and 24in^2 port area, 30hz tuning 2.92ft^3 x 1728 = 5045.76 in^2 24in^2 / 3.14 = 7.64, square root of 7.64 = 7.64^0.5 = 2.76in radius Lv = [ (1.463 x 10^7 x (2.76)^2 ) / (30^2 x 5045.76) ] - 1.463(2.76) = 20.5 inches. So with the net volume of the enclosure being 2.92ft^3, 24in^2 port area, and 30hz tuning, the port length would need to be 20.5 inches. The displacement of the port is portarea x port length, or 24in^2 x 20.5in = 492in^3 or 492in^3 / 1728 = 0.28ft^3 So the internal volume of the enclosure after driver and bracing displacement needs to be 2.92ft^3 + 0.28ft^3 = 3.2ft^3 or 2.92ft^3 with an external port. I hope that sheds some light on the topic.