///M5

This will help a lot!!

Comeon, what about the added deebeez??

*sneakily looks around for used deck*

Nice work young grasshopper. CB, I assume you are satisfied now? In which case, I would say the customer service is spot on. Yes, there was a miscommunication at the factory with the CS rep who didn't know Jeremy but considering the situation I think that is pretty normal. I have seen much larger and smaller companies have similar issues, it is actually quite normal but in this case we have you to thank for making sure that it doesn't happen again.

That is going to be sweet! You will have to post finished pics. As for the triangles, they aren't as easy as slot ports but depending on how you run them in the enclosure are really awesome bracing, plus it looks as if you have enough surface area which is why there is no huffing noises! Great job so far.

Welcome.

I'm with Ryan....

TOP

Your night is 2-3 hours after some of ours.

Mine is the size of a desktop pc, actually just a scope that I bought from Toro when they went digital and cleared out old equipment. $5 wooot!

Perhaps teh potential energy of a skier in a frictionless, oh that's right frictionless doesn't exist. Stupid conservation laws applied in unreal circumstances,.

Ouch, my drilled ones were $72 ea stock Bm'er ones are more than $300 per rotor. My understanding with the cross drilled is that the ones that are crack prone are standard rotors that have been drilled, where the Zimm's supposedly are designed to be drillled. I guess we shall see.

If pennis is a driveway....

If you've got the space which you do and the skills I love the idea.

looks great, like the triangle ports. are you going to cover/paint it?

86 the box and you save weight, but to run IB you need to really seal stuff off.

Can't believe it changed that s to a c???

TOP

chitton in my hair.

Got sand on your pennis?

Sorry Kent

At this point my searching is better than my logic when it comes to classical. Basically it is just a conservation of energy question: add up the Kinetic and potential at both angles and set them equal to each other and bang. You can copy from here: http://web.mit.edu/8.01X/www/probsets/sol8...20snowball'

I will seat them tomorrow as I have to let the paint dry.

bump just in case you missed it I can surely try, and somehow I missed that... thanks A skier starts at the top of a very large, frictionless snowball, with a very small, initial speed, and skis straight down the side. At what point does she lose contact with the snowball and fly off tangent? That is, at the instant she loses contact with the snowball, what angle a does a radial line from the center of the snowball to the skier make with the verticle? i dont even know where to begin By definition tangent is 90 degrees. Sounds like a trick question. i know it's not 90 degrees the skier has a horizontal velocity component as she goes down the ball so that would make her fly off before she reaches 90 degrees Missed the word "radially"

bump just in case you missed it I can surely try, and somehow I missed that... thanks A skier starts at the top of a very large, frictionless snowball, with a very small, initial speed, and skis straight down the side. At what point does she lose contact with the snowball and fly off tangent? That is, at the instant she loses contact with the snowball, what angle a does a radial line from the center of the snowball to the skier make with the verticle? i dont even know where to begin By definition tangent is 90 degrees. Sounds like a trick question.