Hello,

I am building a box for a friend and I had my MDF all ready to cut, measured out panels and everything and he calls and tells me that he want an aeroported box.

I have searched and read different things in this section and after figuring out slot is actually a lot more different than aero ported, I just don't get it.

So, I have come for some box designing help.

Dimensions:

Depth: 16

Height: 16

Width: 40

It is for an Fi X 12.

Was hoping for 2.0ft^3 at 32hz

I really just need to know how many flared aeroports I would need with no port noise. Diameter and Length of the aeroport would be nice.

Thanks in advanced,

Jay

psp-inc

Go with 1 4" Aero and with length go here ... http://www.psp-inc.com/tools.html

Could go with 1 3" as well. Vent mach will be low enough to not be audible.

http://www.linearteam.dk/default.aspx?pageid=ventcalculator

Thanks guys. PSP calc said

2 cubic feet. 32 hz. Port diameter: 4. 1 port.

Length or flared port would need to be 14.066 inches.

Forgot one thing.

I am going to buy this 4" flare and 18" tube and cut it to 15".

How much discplacement would this take up in a box.

Edited November 30, 201014 yr by Hzd Skizzy

Thanks guys. PSP calc said

2 cubic feet. 32 hz. Port diameter: 4. 1 port.

Length or flared port would need to be 14.066 inches.

Forgot one thing.

I am going to buy this 4" flare and 18" tube and cut it to 15".

How much discplacement would this take up in a box.

You do math? lol I'm just kidding:

area of a circle = r^2 x pi

2^2 x pi = 12.56637in squared

12.56637 x 15=188.495559in cubed

Gonna be more than that because 4in is the internal diameter, correct? and the flare itself will take up some room too. Estimate.

Thanks guys. PSP calc said

2 cubic feet. 32 hz. Port diameter: 4. 1 port.

Length or flared port would need to be 14.066 inches.

Forgot one thing.

I am going to buy this 4" flare and 18" tube and cut it to 15".

How much discplacement would this take up in a box.

You do math? lol I'm just kidding:

area of a circle = r^2 x pi

2^2 x pi = 12.56637in squared

12.56637 x 15=188.495559in cubed

Gonna be more than that because 4in is the internal diameter, correct? and the flare itself will take up some room too. Estimate.

Heres what I came up with after some more doing and research.

The whole aeroport will take up .10 cuft. 3.14x2x2x15/1728=.10xxxxx

So the box's internal volume after wood displacement but before port and sub is 2.24-.10 for sub (fi x 12)-.10 for port=2.04 cuft after all displacements tuned at 32hz.

The psp calc for a 2cuft box @ 32hz with a 4" port it would need to be like 14.879 so rounded up to 15''.

I think I've done this right.

Thanks guys. PSP calc said

2 cubic feet. 32 hz. Port diameter: 4. 1 port.

Length or flared port would need to be 14.066 inches.

Forgot one thing.

I am going to buy this 4" flare and 18" tube and cut it to 15".

How much discplacement would this take up in a box.

You do math? lol I'm just kidding:

area of a circle = r^2 x pi

2^2 x pi = 12.56637in squared

12.56637 x 15=188.495559in cubed

Gonna be more than that because 4in is the internal diameter, correct? and the flare itself will take up some room too. Estimate.

Heres what I came up with after some more doing and research.

The whole aeroport will take up .10 cuft. 3.14x2x2x15/1728=.10xxxxx

So the box's internal volume after wood displacement but before port and sub is 2.24-.10 for sub (fi x 12)-.10 for port=2.04 cuft after all displacements tuned at 32hz.

The psp calc for a 2cuft box @ 32hz with a 4" port it would need to be like 14.879 so rounded up to 15''.

I think I've done this right.

Looking good. Now just slap it together and bump!