The bridge you are referring to (as pointed out by M5) failed not necessarily because it was excited at resonance, but because it was excited at resonance and driven beyond it's mechanical limitations. Just the same a subwoofer would be damaged if you drove it past it's mechanical limits. But going back to our weight on a spring...what happens when the weight is pulled downward and released? Does the spring oscillate until it self destructs, or does it oscillate until it's energy is expended? So, how do we determine the time it takes a subwoofer excited at resonance to dissipate it's energy and cease oscillation? By the Q factor. The Q of the driver describes the amount of damping provided at resonance, or for how long after the signal is removed the driver will continue to "ring". (The terms "overshoot" and "ringing" are commonly used to express the amount of damping a driver has.) Qms is mechanical damping (i.e. the suspension). Qes is the electrical damping (i.e. the motor). And Qts is the total Q of the driver (Qts = Qms * Qes/Qms + Qes). A high Q indicates a driver that is underdamped, meaning it will "ring" for a longer period of time or that it has more "overshoot". A low Q indicates a driver is more overdamped, meaning it will have less "ringing" or less "overshoot". So the Qts tells us how a driver will behave at Fs based on the damping provided by the motor and the suspension. And, in case you've never noticed...in the vast majority of drivers on the market, the Qms is much higher than the Qes. Likewise, the total Q of the driver (Qts) is typically just slightly lower than the Qes and significantly lower than Qms. So what does this mean? It tells us that the motor provides much more damping and control over the motion of the cone than the suspension. Well, the impedance does increase but I don't believe "rise" is typically the word used to express that idea as that's most associated with enclosure and heat effects, again as M5 pointed out.