^^ This guys, not everyone is as familiar with this process as some of us may be. Like Sean said, play a 2500hz tone with the crossover set to off or flat and measure the output voltage (DMM should be set to measure AC Volts). It doesn't really matter what the voltage output is at this point. We are simply measuring the output voltage now so that we have a baseline to work from. To find the -3db point, and your target voltage, you would multiply the voltage you measured by .707. Then turn the crossover back on and adjust the crossover dial until the voltage decreases to the target voltage you just calculated. When the voltage reaches that target voltage, the crossover is set to 2500hz. So, for example, let's say you play the 2500hz test tone and measure an output voltage of 5V with the crossover set to flat (or off). Then your target voltage for a 2500hz crossover point would 5 * .707 = 3.535V. So turn the crossover on and measure the output voltage while adjusting the crossover knob. When the output voltage drops to 3.54V, that's the -3db point of the signal.....meaning you successfully set the crossover to 2500hz. For those that don't know, for a standard Butterworth crossover (the type of crossover found in most, but not all, amplifiers) the crossover point is defined as the -3db point of the signal. Hence why we know that the crossover is set to 2500hz when the signal has decreased by -3db. And we calculate the -3db point of the signal as the point where the signal has decreased to .707 of it's original value because for voltage the conversion to decibels is 20*log(Voltage1/Voltage2). So 20*log(1 / .707) = 3.01db. Therefore, the point where the signal has decreased to .707 of it's original value is the -3db point of the signal, and the -3db point of the signal defines the crossover point Now you know, and knowing is half the battle.