Well, I'm bored, so we're going to go through the math anyways. Let's say you have a 1000w amp and two dual 2ohm subwoofers wired to a final 2ohm load. First, let's find out the total voltage and current output of the amplifier. Using basic ohm's law, we find: Voltage = sqrt(voltage * resistance) = sqrt(1000*2) = 44.72V Current = Watts/Volts = 1000/44.72 = 22.36A And, to verify we are right, 44.72 * 22.36 = 1000w. Cool, step 1 complete. Now let's find out out much voltage and current each speaker is receiving. Let's just look at the two drivers on the "whole", forget about individual coils right now. Each driver is 4ohm (since the individual coils are wired in series) and the two drivers are wired in parallel. One thing we know about parallel circuits is that the voltage is the same across the resistors, so we know each driver is going to be seeing 44.72V. To figure out how much current each driver is going to see, we divide the voltage by their resistance; Current = Volt/Resistance = 44.72/4 = 11.18A So how much power is each driver receiving? Simply multiple voltage and current; 44.72V * 11.18A = 500w. Cool, so we know each driver is going to see 500w. Now, how much power is each coil going to receive? Well, in a series circuit, the voltage is "split" between the resistors and current stays the same. So current to each coil is 11.18A. Voltage = Amps * Resistance = 11.18 * 2 = 22.36V And power to each coil is voltage multiplied by current; 22.36 * 11.18 = 250w to each individual coil. So, there it is. Basic Ohms Law. Each coil will receive 250w. Or, since all of the "resistors" (coils) are the same resistance......we can skip all of that headache and just divide the power by the number of coils; 1000/4 = 250w. You would really only need to bust out Ohms Law to figure this out if you had drivers that were different impedances. And then it gets a little more hairy.